+
+
+function member_of($c) {
+
+ $r = q("SELECT `group`.`name`, `group`.`id` FROM `group` LEFT JOIN `group_member` ON `group_member`.`gid` = `group`.`id` WHERE `group_member`.`contact-id` = %d AND `group`.`deleted` = 0 ORDER BY `group`.`name` ASC ",
+ intval($c)
+ );
+
+ return $r;
+
+}
+