// "Getter" for result from given table and field/type LIKEs
function sqlGetResultFromLikeColumnsType ($tableName, $field, $type) {
// The table should be there
- assert(ifSqlTableExists($tableName), 'tableName=' . $tableName . ' does not exist. field=' . $field . ',type=' . $type);
+ assert(ifSqlTableExists($tableName));
// Default no field set
$fieldSql = '';